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0.3x^2+7x-121.1=0
a = 0.3; b = 7; c = -121.1;
Δ = b2-4ac
Δ = 72-4·0.3·(-121.1)
Δ = 194.32
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{194.32}}{2*0.3}=\frac{-7-\sqrt{194.32}}{0.6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{194.32}}{2*0.3}=\frac{-7+\sqrt{194.32}}{0.6} $
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